Show 'part of' in candidate list
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parent
9457d423aa
commit
53ba0d7845
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@ -146,6 +146,11 @@
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<span v-if="osm.address_list.length">
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<br>address nodes: {{ osm.address_list.join("; ") }}
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</span>
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<span v-if="osm.part_of">
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<br>part of: {{ osm.part_of.join("; ") }}
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</span>
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</td>
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</tr>
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</tbody>
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19
web_view.py
19
web_view.py
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@ -951,6 +951,21 @@ def get_address_nodes_within_building(building, bbox):
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return [node.tags for node in q]
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def get_part_of(thing, bbox):
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db_bbox = make_envelope(bbox)
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ewkt = thing.as_EWKT
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q = model.Polygon.query.filter(
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func.ST_Intersects(db_bbox, model.Polygon.way),
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func.ST_Covers(model.Polygon.way, func.ST_GeomFromEWKT(ewkt)),
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or_(
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model.Polygon.tags.has_key("landuse"),
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model.Polygon.tags.has_key("amenity"),
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),
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model.Polygon.tags.has_key("name"),
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)
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return [polygon.tags for polygon in q]
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def address_from_tags(tags):
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keys = ["street", "housenumber"]
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if g.street_number_first:
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@ -989,6 +1004,10 @@ def api_find_osm_candidates(item_id):
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if hasattr(osm, 'area'):
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cur["area"] = osm.area
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part_of = [i["name"] for i in get_part_of(osm, bounds) if i["name"] != name]
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if part_of:
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cur["part_of"] = part_of
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nearby.append(cur)
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t1 = time() - t0
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