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Economist summer and Christmas double issues

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Closes: #9
This commit is contained in:
Edward Betts 2023-10-03 09:27:14 +01:00
parent b68654e4ac
commit 14133f591c
1 changed files with 27 additions and 4 deletions
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31
agenda/__init__.py
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@ -152,10 +152,33 @@ def get_gbpusd() -> Decimal:
return typing.cast(Decimal, 1 / data["quotes"]["USDGBP"])
def next_economist() -> date:
def next_economist(input_date: date) -> date:
"""Next date that the Economist is published."""
# TODO: handle the Christmas double issue correctly
return today + timedelta((3 - today.weekday()) % 7)
# Define the publication day (Thursday) and the day of the week of the input date
publication_day = 3 # Thursday (0 - Monday, 1 - Tuesday, ..., 6 - Sunday)
current_day_of_week = input_date.weekday()
current_week_number = today.isocalendar().week
# Define the list of weeks when The Economist is not published
non_publication_weeks = [26, 56]
# Check if the input date is a publication day (Thursday)
if (
current_day_of_week == publication_day
and current_week_number not in non_publication_weeks
):
return input_date
# Calculate the date for the next Thursday after the input date
days_until_next_thursday = (publication_day - current_day_of_week + 7) % 7
next_thursday_date = input_date + timedelta(days=days_until_next_thursday)
# Check if the next Thursday falls in a non-publication week
while next_thursday_date.isocalendar().week in non_publication_weeks:
# If it does, add 7 days to find the next Thursday
next_thursday_date += timedelta(days=7)
return next_thursday_date
def timedelta_display(delta: timedelta) -> str:
@ -225,7 +248,7 @@ def get_data() -> dict[str, str | object]:
reply = {
"now": now,
"gbpusd": get_gbpusd(),
"next_economist": next_economist(),
"next_economist": next_economist(today),
"bank_holiday": get_next_bank_holiday(),
"us_holiday": get_us_holiday(),
"next_uk_general_election": next_uk_general_election,