parent
b68654e4ac
commit
14133f591c
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@ -152,10 +152,33 @@ def get_gbpusd() -> Decimal:
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return typing.cast(Decimal, 1 / data["quotes"]["USDGBP"])
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def next_economist() -> date:
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def next_economist(input_date: date) -> date:
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"""Next date that the Economist is published."""
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# TODO: handle the Christmas double issue correctly
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return today + timedelta((3 - today.weekday()) % 7)
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# Define the publication day (Thursday) and the day of the week of the input date
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publication_day = 3 # Thursday (0 - Monday, 1 - Tuesday, ..., 6 - Sunday)
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current_day_of_week = input_date.weekday()
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current_week_number = today.isocalendar().week
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# Define the list of weeks when The Economist is not published
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non_publication_weeks = [26, 56]
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# Check if the input date is a publication day (Thursday)
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if (
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current_day_of_week == publication_day
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and current_week_number not in non_publication_weeks
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):
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return input_date
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# Calculate the date for the next Thursday after the input date
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days_until_next_thursday = (publication_day - current_day_of_week + 7) % 7
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next_thursday_date = input_date + timedelta(days=days_until_next_thursday)
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# Check if the next Thursday falls in a non-publication week
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while next_thursday_date.isocalendar().week in non_publication_weeks:
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# If it does, add 7 days to find the next Thursday
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next_thursday_date += timedelta(days=7)
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return next_thursday_date
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def timedelta_display(delta: timedelta) -> str:
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@ -225,7 +248,7 @@ def get_data() -> dict[str, str | object]:
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reply = {
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"now": now,
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"gbpusd": get_gbpusd(),
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"next_economist": next_economist(),
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"next_economist": next_economist(today),
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"bank_holiday": get_next_bank_holiday(),
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"us_holiday": get_us_holiday(),
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"next_uk_general_election": next_uk_general_election,
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