Edward Betts
ea4980a5d7
Adjust European short trip heuristic from >3 days to >1 day to correctly detect when user has returned home from European trips. This fixes the April 29-30, 2023 case where the location incorrectly showed "Sankt Georg, Hamburg" instead of "Bristol" when the user was free (no events scheduled) after the foss-north trip ended on April 27. The previous logic required more than 3 days to pass before assuming return home from European countries, but for short European trips by rail/ferry, users typically return within 1-2 days. 🤖 Generated with [Claude Code](https://claude.ai/code) Co-Authored-By: Claude <noreply@anthropic.com>
59 lines
1.5 KiB
JavaScript
59 lines
1.5 KiB
JavaScript
//TODO: handle reviver/dehydrate function like normal
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//and handle indentation, like normal.
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//if anyone needs this... please send pull request.
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exports.stringify = function stringify (o) {
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if('undefined' == typeof o) return o
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if(o && Buffer.isBuffer(o))
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return JSON.stringify(':base64:' + o.toString('base64'))
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if(o && o.toJSON)
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o = o.toJSON()
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if(o && 'object' === typeof o) {
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var s = ''
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var array = Array.isArray(o)
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s = array ? '[' : '{'
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var first = true
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for(var k in o) {
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var ignore = 'function' == typeof o[k] || (!array && 'undefined' === typeof o[k])
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if(Object.hasOwnProperty.call(o, k) && !ignore) {
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if(!first)
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s += ','
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first = false
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if (array) {
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if(o[k] == undefined)
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s += 'null'
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else
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s += stringify(o[k])
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} else if (o[k] !== void(0)) {
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s += stringify(k) + ':' + stringify(o[k])
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}
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}
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}
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s += array ? ']' : '}'
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return s
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} else if ('string' === typeof o) {
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return JSON.stringify(/^:/.test(o) ? ':' + o : o)
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} else if ('undefined' === typeof o) {
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return 'null';
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} else
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return JSON.stringify(o)
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}
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exports.parse = function (s) {
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return JSON.parse(s, function (key, value) {
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if('string' === typeof value) {
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if(/^:base64:/.test(value))
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return Buffer.from(value.substring(8), 'base64')
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else
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return /^:/.test(value) ? value.substring(1) : value
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}
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return value
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})
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}
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