Edward Betts
ea4980a5d7
Adjust European short trip heuristic from >3 days to >1 day to correctly detect when user has returned home from European trips. This fixes the April 29-30, 2023 case where the location incorrectly showed "Sankt Georg, Hamburg" instead of "Bristol" when the user was free (no events scheduled) after the foss-north trip ended on April 27. The previous logic required more than 3 days to pass before assuming return home from European countries, but for short European trips by rail/ferry, users typically return within 1-2 days. 🤖 Generated with [Claude Code](https://claude.ai/code) Co-Authored-By: Claude <noreply@anthropic.com>
60 lines
1.4 KiB
JavaScript
60 lines
1.4 KiB
JavaScript
var test = require('tape');
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var stringify = require('../');
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test('space parameter', function (t) {
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t.plan(1);
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var obj = { one: 1, two: 2 };
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t.equal(stringify(obj, {space: ' '}), ''
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+ '{\n'
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+ ' "one": 1,\n'
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+ ' "two": 2\n'
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+ '}'
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);
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});
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test('space parameter (with tabs)', function (t) {
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t.plan(1);
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var obj = { one: 1, two: 2 };
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t.equal(stringify(obj, {space: '\t'}), ''
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+ '{\n'
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+ '\t"one": 1,\n'
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+ '\t"two": 2\n'
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+ '}'
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);
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});
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test('space parameter (with a number)', function (t) {
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t.plan(1);
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var obj = { one: 1, two: 2 };
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t.equal(stringify(obj, {space: 3}), ''
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+ '{\n'
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+ ' "one": 1,\n'
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+ ' "two": 2\n'
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+ '}'
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);
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});
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test('space parameter (nested objects)', function (t) {
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t.plan(1);
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var obj = { one: 1, two: { b: 4, a: [2,3] } };
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t.equal(stringify(obj, {space: ' '}), ''
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+ '{\n'
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+ ' "one": 1,\n'
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+ ' "two": {\n'
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+ ' "a": [\n'
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+ ' 2,\n'
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+ ' 3\n'
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+ ' ],\n'
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+ ' "b": 4\n'
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+ ' }\n'
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+ '}'
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);
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});
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test('space parameter (same as native)', function (t) {
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t.plan(1);
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// for this test, properties need to be in alphabetical order
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var obj = { one: 1, two: { a: [2,3], b: 4 } };
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t.equal(stringify(obj, {space: ' '}), JSON.stringify(obj, null, ' '));
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});
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