Adjust European short trip heuristic from >3 days to >1 day to correctly detect when user has returned home from European trips. This fixes the April 29-30, 2023 case where the location incorrectly showed "Sankt Georg, Hamburg" instead of "Bristol" when the user was free (no events scheduled) after the foss-north trip ended on April 27. The previous logic required more than 3 days to pass before assuming return home from European countries, but for short European trips by rail/ferry, users typically return within 1-2 days. 🤖 Generated with [Claude Code](https://claude.ai/code) Co-Authored-By: Claude <noreply@anthropic.com>
34 lines
983 B
JavaScript
34 lines
983 B
JavaScript
var test = require('tape'),
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wildcard = require('../'),
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testdata = [
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'a.b.c',
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'a.b',
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'a',
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'a.b.d'
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],
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testdataSep = [
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'a:b:c',
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'a:b',
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'a',
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'a:b:d'
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];
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test('array result matching tests', function(t) {
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t.plan(5);
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t.equal(wildcard('*', testdata).length, 4, '* matches all testdata');
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t.equal(wildcard('a.*', testdata).length, 4, '4 matches found');
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t.equal(wildcard('a.b.*', testdata).length, 3, '3 matches found');
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t.equal(wildcard('a.*.c', testdata).length, 1);
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t.equal(wildcard('b.*.d', testdata).length, 0);
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});
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test('array result with separator matching tests', function(t) {
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t.plan(4);
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t.equal(wildcard('a:*', testdataSep, ':').length, 4, '4 matches found');
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t.equal(wildcard('a:b:*', testdataSep, ':').length, 3, '3 matches found');
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t.equal(wildcard('a:*:c', testdataSep, ':').length, 1);
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t.equal(wildcard('b:*:d', testdataSep, ':').length, 0);
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});
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