Edward Betts
ea4980a5d7
Adjust European short trip heuristic from >3 days to >1 day to correctly detect when user has returned home from European trips. This fixes the April 29-30, 2023 case where the location incorrectly showed "Sankt Georg, Hamburg" instead of "Bristol" when the user was free (no events scheduled) after the foss-north trip ended on April 27. The previous logic required more than 3 days to pass before assuming return home from European countries, but for short European trips by rail/ferry, users typically return within 1-2 days. 🤖 Generated with [Claude Code](https://claude.ai/code) Co-Authored-By: Claude <noreply@anthropic.com>
23 lines
717 B
TypeScript
23 lines
717 B
TypeScript
import type {CodeKeywordDefinition, AnySchema} from "../../types"
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import type {KeywordCxt} from "../../compile/validate"
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import {alwaysValidSchema} from "../../compile/util"
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const def: CodeKeywordDefinition = {
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keyword: "allOf",
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schemaType: "array",
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code(cxt: KeywordCxt) {
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const {gen, schema, it} = cxt
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/* istanbul ignore if */
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if (!Array.isArray(schema)) throw new Error("ajv implementation error")
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const valid = gen.name("valid")
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schema.forEach((sch: AnySchema, i: number) => {
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if (alwaysValidSchema(it, sch)) return
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const schCxt = cxt.subschema({keyword: "allOf", schemaProp: i}, valid)
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cxt.ok(valid)
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cxt.mergeEvaluated(schCxt)
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})
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},
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}
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export default def
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