Adjust European short trip heuristic from >3 days to >1 day to correctly detect when user has returned home from European trips. This fixes the April 29-30, 2023 case where the location incorrectly showed "Sankt Georg, Hamburg" instead of "Bristol" when the user was free (no events scheduled) after the foss-north trip ended on April 27. The previous logic required more than 3 days to pass before assuming return home from European countries, but for short European trips by rail/ferry, users typically return within 1-2 days. 🤖 Generated with [Claude Code](https://claude.ai/code) Co-Authored-By: Claude <noreply@anthropic.com>
58 lines
1.3 KiB
JavaScript
58 lines
1.3 KiB
JavaScript
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/*
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* @version 1.4.0
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* @date 2015-10-26
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* @stability 3 - Stable
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* @author Lauri Rooden (https://github.com/litejs/natural-compare-lite)
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* @license MIT License
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*/
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var naturalCompare = function(a, b) {
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var i, codeA
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, codeB = 1
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, posA = 0
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, posB = 0
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, alphabet = String.alphabet
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function getCode(str, pos, code) {
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if (code) {
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for (i = pos; code = getCode(str, i), code < 76 && code > 65;) ++i;
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return +str.slice(pos - 1, i)
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}
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code = alphabet && alphabet.indexOf(str.charAt(pos))
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return code > -1 ? code + 76 : ((code = str.charCodeAt(pos) || 0), code < 45 || code > 127) ? code
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: code < 46 ? 65 // -
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: code < 48 ? code - 1
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: code < 58 ? code + 18 // 0-9
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: code < 65 ? code - 11
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: code < 91 ? code + 11 // A-Z
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: code < 97 ? code - 37
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: code < 123 ? code + 5 // a-z
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: code - 63
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}
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if ((a+="") != (b+="")) for (;codeB;) {
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codeA = getCode(a, posA++)
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codeB = getCode(b, posB++)
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if (codeA < 76 && codeB < 76 && codeA > 66 && codeB > 66) {
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codeA = getCode(a, posA, posA)
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codeB = getCode(b, posB, posA = i)
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posB = i
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}
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if (codeA != codeB) return (codeA < codeB) ? -1 : 1
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}
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return 0
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}
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try {
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module.exports = naturalCompare;
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} catch (e) {
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String.naturalCompare = naturalCompare;
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}
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