Edward Betts
ea4980a5d7
Adjust European short trip heuristic from >3 days to >1 day to correctly detect when user has returned home from European trips. This fixes the April 29-30, 2023 case where the location incorrectly showed "Sankt Georg, Hamburg" instead of "Bristol" when the user was free (no events scheduled) after the foss-north trip ended on April 27. The previous logic required more than 3 days to pass before assuming return home from European countries, but for short European trips by rail/ferry, users typically return within 1-2 days. 🤖 Generated with [Claude Code](https://claude.ai/code) Co-Authored-By: Claude <noreply@anthropic.com>
47 lines
962 B
JavaScript
47 lines
962 B
JavaScript
/*
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MIT License http://www.opensource.org/licenses/mit-license.php
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Author Tobias Koppers @sokra
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*/
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"use strict";
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/**
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* @template T
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* @param {Iterable<T>} set a set
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* @returns {T | undefined} last item
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*/
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const last = set => {
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let last;
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for (const item of set) last = item;
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return last;
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};
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/**
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* @template T
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* @param {Iterable<T>} iterable iterable
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* @param {function(T): boolean} filter predicate
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* @returns {boolean} true, if some items match the filter predicate
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*/
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const someInIterable = (iterable, filter) => {
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for (const item of iterable) {
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if (filter(item)) return true;
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}
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return false;
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};
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/**
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* @template T
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* @param {Iterable<T>} iterable an iterable
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* @returns {number} count of items
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*/
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const countIterable = iterable => {
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let i = 0;
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// eslint-disable-next-line no-unused-vars
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for (const _ of iterable) i++;
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return i;
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};
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exports.last = last;
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exports.someInIterable = someInIterable;
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exports.countIterable = countIterable;
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